Christopher Ball wrote: > In Python, a/0 gives a divide-by-zero error for any a, but in numpy, I > can ignore divide-by-zero errors. If I do this, why can't I still have > 0/0 be nan? > > seterr(divide='ignore') > a=array([0],dtype=float_) > b=array([0],dtype=float_) > divide(a,b) > > gives nan, so why doesn't > > seterr(divide='ignore') > a=array([0],dtype=int_) > b=array([0],dtype=int_) > divide(a,b) > > also give nan, rather than 0 as it gives now? Is this because inf is not > something to which an int can be set (as Christopher Barker wrote), and > it matches Python's behavior?
Pretty much. ints operated with ints will give ints, not floats. nan and inf are floating point concepts. -- Robert Kern "I have come to believe that the whole world is an enigma, a harmless enigma that is made terrible by our own mad attempt to interpret it as though it had an underlying truth." -- Umberto Eco _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
