On Thursday 08 February 2007 16:21:09 [EMAIL PROTECTED] wrote: > > I'm very surprised by the line noted. I always thinking that the input > variable didn't change the variable itself outside the function.
Except that in this particular case, you explicitly change the input array itself by using an inplace operator. > I can't keep the input variable if I'm not doing a copy before to call a > function... what about just using var1 = var1*3 ? That way, the initial array is left intact, and var1 inside your function is multiplied by 3. _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion
