Say I use a function that expects a boolean array called sel to be passed as an argument:
def foo(x,sel = None): return x[sel] If x is a 1-d array and sel is a (1-d) boolean array, x.shape will give (n,) where n is len(x). However, if the default value None is used (i.e., when no boolean array is passed) x.shape will give (1,n). Is that expected behavior? If so is there an alternative default to I could use that would return the entire x array and have x.shape be (n,)? Vincent _______________________________________________ Numpy-discussion mailing list Numpy-discussion@scipy.org http://projects.scipy.org/mailman/listinfo/numpy-discussion