On Sun, 2015-09-20 at 15:07 -0400, Aaron Conole wrote:
> Eric Dumazet <eric.duma...@gmail.com> writes:
> 
> > On Sun, 2015-09-20 at 05:18 -0400, Aaron Conole wrote:
> >> From: Aaron Conole <aa...@bytheb.org>
> >> 
> >
> > I am wondering what this is expected to do, and how this code would
> > possibly not trigger a crash.
> Are you suspecting it should crash from a possible double-lock case?
> On line 2125, there is an unconditional unlock, which should be 
> guaranteeing that there is no longer a condition to 'double lock' the
> socket.

Not at all.

I am suggesting there is a big difference between

unix_state_lock(&sk);

and

unix_state_lock(sk);

Can you see it ?



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