Eric Dumazet wrote, On 12/14/2007 12:09 PM:
...

> +     /*
> +      * Instead of returning hash % ht->cfg.size (implying a divide)
> +      * we return the high 32 bits of the (hash * ht->cfg.size) that will
> +      * give results between [0 and cfg.size-1] and same hash distribution,
> +      * but using a multiply, less expensive than a divide
> +      */
> +     return ((u64)hash * ht->cfg.size) >> 32;

Are we sure of the same hash distribution? Probably I miss something,
but: if this 'hash' is well distributed on 32 bits, and ht->cfg.size
is smaller than 32 bits, e.g. 256 (8 bits), then this multiplication
moves to the higher 32 of u64 only max. 8 bits of the most significant
byte, and the other three bytes are never used, while division is
always affected by all four bytes...

Regards,
Jarek P.
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