In article <[EMAIL PROTECTED]> (at Wed, 7 Nov 2007 10:52:47 -0800), "Templin,
Fred L" <[EMAIL PROTECTED]> says:
> > > > > > + if (((ipv4 >= 0x01000000) && (ipv4 < 0x0a000000)) ||
> > > > > > + ((ipv4 >= 0x0b000000) && (ipv4 < 0x7f000000)) ||
> > > > > > + ((ipv4 >= 0x80000000) && (ipv4 < 0xa9fe0000)) ||
> > > > > > + ((ipv4 >= 0xa9ff0000) && (ipv4 < 0xac100000)) ||
> > > > > > + ((ipv4 >= 0xac200000) && (ipv4 < 0xc0a80000)) ||
> > > > > > + ((ipv4 >= 0xc0a90000) && (ipv4 < 0xc6120000)) ||
> > > > > > + ((ipv4 >= 0xc6140000) && (ipv4 <
> > 0xe0000000))) eui[0] |=
> > > > > > 0x2;
> Maybe it is I who did not understand. Can you suggest a clean solution?
You could write each element as LOOPBACK(), MULTICAST()
etc.
eui[0] = (!ZERONETO(a) &&
!PRIVATE_10(a) &&
!LINKLOCAL(a) &&
!PRIVATE_172(a) &&
!PRIVATE_192(a) &&
!NETICDEVBENCH(a) &&
!MULTICAST(a)) ? 2 : 0;
--yoshfuji
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