I can reproduce this on 4.19.0-3-amd64 both with, and without the JIT enabled.

Dumping the "root" and "non-root" programs with bpftool,
the subtraction instructions differ:

"non-root":
   0: (85) call bpf_ktime_get_ns#74944
   1: (bf) r7 = r0
   2: (85) call bpf_ktime_get_ns#74944
   3: (bf) r6 = r0
   4: (bf) r8 = r6
   5: (b4) w11 = -1
   6: (1f) r11 -= r8
   7: (4f) r11 |= r8
   8: (87) r11 = -r11
   9: (c7) r11 s>>= 63
  10: (5f) r8 &= r11

"root":
   0: (85) call bpf_ktime_get_ns#74944
   1: (bf) r7 = r0
   2: (85) call bpf_ktime_get_ns#74944
   3: (bf) r6 = r0
   4: (bf) r8 = r6

The remainder of the instructions are for writing the results in the map,
and the instructions are identical.

I believe the extra instructions come from "fixup_bpf_calls" in the verifier:

    if (isneg)
        *patch++ = BPF_ALU64_IMM(BPF_MUL, off_reg, -1);
    *patch++ = BPF_MOV32_IMM(BPF_REG_AX, aux->alu_limit - 1);
    *patch++ = BPF_ALU64_REG(BPF_SUB, BPF_REG_AX, off_reg);
    *patch++ = BPF_ALU64_REG(BPF_OR, BPF_REG_AX, off_reg);
    *patch++ = BPF_ALU64_IMM(BPF_NEG, BPF_REG_AX, 0);
    *patch++ = BPF_ALU64_IMM(BPF_ARSH, BPF_REG_AX, 63);
    if (issrc) {
        *patch++ = BPF_ALU64_REG(BPF_AND, BPF_REG_AX,
                     off_reg);
        insn->src_reg = BPF_REG_AX;
    } else {
        *patch++ = BPF_ALU64_REG(BPF_AND, off_reg,
                     BPF_REG_AX);
    }

This was introduced by "bpf: prevent out of bounds speculation on pointer 
arithmetic"
(https://patchwork.ozlabs.org/patch/1039606/).
I don't yet understand what's going on.

Cheers,

Arthur

Reply via email to