Evgeniy Polyakov wrote:
> On Tue, Apr 18, 2006 at 01:13:35AM +0200, Patrick McHardy ([EMAIL PROTECTED]) 
> wrote:
> 
>>I went over your mails again, but I don't understand the problem you're
>>seeing. Please just make a simple example showing the operation +
>>the arguments you're using to bind to group 5 which would result in
>>bit 0 beeing set or the kernel deciding to send to group 1 for some
>>other reason.
> 
> 
> Example:
> at bind time group 5 was selected and then socket was subscribed to that
> group. This end up in 0b10101 bitmask, which allows to multicast to
> group 16 which has nothing in common with either group number 5 or
> bitmask 5.

Again, bind() takes a bitmask of the groups to subscribe to, not the
numerical value 5. To subscribe to group 5 using bind, you use 1<<(5-1)
as nladdr, which is 0x10000. Check out the difference between
RTMGRP_NOTIFY (backwards compatibility for bind()) and RTNLGRP_NOTIFY
(used internally and for NETLINK_ADD_MEMBERSHIP).

> I think that if socket uses bitmask at bind time, then it should not be
> allowed to subscribe.
> So for above example at bind time (1<<4) should be used and this is what
> happens with subscription. We discussed already that itmask
> functionality was never used, and current behaviour introduces big
> ambiguity.
> Well, if you forces this to not be changed, I will update documentation
> about this behaviour.

See above. Does this clear things up?

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