An expression of the form '(a | b) & b' will evaluate to the value of b for any value of a or b.
Signed-off-by: Phil Sutter <p...@nwl.cc> --- misc/ss.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/misc/ss.c b/misc/ss.c index 38cf3312a746e..d6090018c5dbb 100644 --- a/misc/ss.c +++ b/misc/ss.c @@ -267,7 +267,7 @@ static void filter_default_dbs(struct filter *f) static void filter_states_set(struct filter *f, int states) { if (states) - f->states = (f->states | states) & states; + f->states = states; } static void filter_merge_defaults(struct filter *f) -- 2.8.0