On 7 September 2012 12:38, Sverre Moe <[email protected]> wrote:
> Yes it is a group of scalar. In my little example it is only one group, but
> it can potentially be many groups. There will never be other groups in a
> group that has scalars, but one group can have 2 group of scalars.
>
> For example it could be something like this. Can all these scalar be counted
> in the main group of test, or the groups of test1, test2, test31 and test32?
No - you would need to register each group individually.
Remember - there must always be something within the code that
implements a given MIB that tells the agent which OIDs correspond
to valid MIB objects.
In the case of the scalar_group helper, the code takes the "root"
OID, and appends each of the subidentifiers from within the range
given in the registration.
So
netsnmp_register_scalar_group( "root", first, last );
is a shorthand for
register root.first
register root.first+1
:
register root.last
There's not really an easy way to tell the agent
register root.group1.obj1
register root.group1.obj2
:
register root.group1.objN
register root.group2.obj1
register root.group2.obj2
:
register root.group2.objM
register root.group3.group3a.obj1
register root.group3.group3a.obj2
:
register root.group3.group3a.objX
register root.group3.group3b.obj1
register root.group3.group3b.obj2
:
register root.group3.group3b.objY
How would you go about specifying this level
of complexity within a single
netsnmp_register_complex( ... )
call?
(Let alone the rats' nest of code that would be
needed to process such a registration).
It's a lot easier to have a registration helper for
a simple group, and let the initialisation code
take care of the heirarchical complexities:
netsnmp_register_scalar_group( root.group1, 1, M );
netsnmp_register_scalar_group( root.group2, 1, N );
netsnmp_register_scalar_group( root.group3.group3a, 1, X );
netsnmp_register_scalar_group( root.group3.group3b, 1, Y );
Dave
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