On Fri, Jun 05, 2009 at 12:27:12PM -0400, Ted Unangst wrote:
On Fri, Jun 5, 2009 at 12:15 PM, Ted Walther <[email protected]> wrote:
execve() wants ? char *const envp[]
environ provides char **
environ is provided by execve from envp.
How do I pass the environment into execve without raising a compiler
warning about incompatible pointer types?
What warning are you getting? What's your source?
My apologies. I was abusing "const". I must have been using the
function prototype from an other OS than OpenBSD.
Here was my sample that caused the error:
====
#include <unistd.h>
#include <stdlib.h>
extern char **environ;
void
my_exec(const char *f, const char *const *a, const char *const *e) {
/* do some stuff ... then: */
execve(f,a,e);
}
int
main(int argc, char **argv) {
my_exec(*argv,argv+1,environ);
exit(0);
}
====
The fix was to remove the extraneous consts from arg2 and arg3.
-my_exec(const char *f, const char *const *a, const char *const *e) {
+my_exec(const char *f, char *const a[], char *const e[]) {
Ted
--
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