Hello!
On Sun, Aug 21, 2005 at 09:54:06AM +0200, Alexander Farber wrote:
> if (!noclose && (fd = open(_PATH_DEVNULL, O_RDWR, 0)) != -1) {
> (void)dup2(fd, 0);
> (void)dup2(fd, 1);
> (void)dup2(fd, 2);
> if (fd > 2)
> (void)close (fd);
> }
>right? What is this last check (fd > 2) needed for? Isn't fd always > 2,
>because the first 3 are already taken by the STDxxx streams at the
>program start?
What if any of the descriptors <= 2 are closed before invocation
of daemon? Then fd will be <= 2, and if you close it, the desired
state (/dev/null open on 0, 1, and 2) will not be achieved.
I.e. safety.
>Thanks
>Alex
Kind regards,
Hannah.
