what's going on? GlobalMemoryStatusEx() always returns failure. I even memset()
the struct with 0's, no difference.
#include <iostream>
#Include <memory.h>
#include <windows.h>
#include <stdint.h>
#include <WinBase.h>
typedef uint64_t addressType; //with 64-bit boxes, there may be support for
__int128, but I guess not yet with some compilers
typedef uint64_t vecElementType;
MEMORYSTATUSEX mse;
addressType availableRAM(void) {
memset(&mse,0, sizeof(MEMORYSTATUSEX));
if (0==GlobalMemoryStatusEx(&mse)) {
std::cout<<"GlobalMemoryStatusEx():ERROR\n";
return 0;
}
addressType ram=mse.ullAvailPhys;
std::cout<<"availableRam()="<<ram<<"\n";
return ram; //do I need to use a percentage here? is there a structure
overhead with bitset?
}
int main(int argc, char * argv[]) {
UINT_TYPE n=0;
size_t sp,ep;
availRam = availableRAM();
if (0!=availRam) {
availRam -= RESERVE_RAM;//2*2^30. we reserve 2GiB for applications to
run fast like browsers etc
}
return 0;
}
-------------
Jim Michaels
jmich...@yahoo.com
j...@renewalcomputerservices.com
http://RenewalComputerServices.com
http://JesusnJim.com (my personal site, has software)
---
IEC Units: Computer RAM & SSD measurements, microsoft disk size measurements
(note: they will say GB or MB or KB or TB when it is IEC Units!):
[KiB] [MiB] [GiB] [TiB]
[2^10B=1,024^1B=1KiB]
[2^20B=1,024^2B=1,048,576B=1MiB]
[2^30B=1,024^3B=1,073,741,824B=1GiB]
[2^40B=1,024^4B=1,099,511,627,776B=1TiB]
[2^50B=1,024^5B=1,125,899,906,842,624B=1PiB]
SI Units: Hard disk industry disk size measurements:
[KB] [MB] [GB] [TB]
[10^3B=1,000B=1KB]
[10^6B=1,000,000B=1MB]
[10^9B=1,000,000,000B=1GB]
[10^12B=1,000,000,000,000B=1TB]
[10^15B=1,000,000,000,000,000B=1PB]------------------------------------------------------------------------------
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