Hello, Le 2012-07-04 17:46, niXman a écrit : > The following code gives the right result when compiled without
Which right result exactly ? My reading of MSDN suggests a negative return value. > defined __USE_MINGW_ANSI_STDIO macro. > But, if __USE_MINGW_ANSI_STDIO macro is defined - the result is 6. > Why? http://pubs.opengroup.org/onlinepubs/009695399/functions/snprintf.html Upon successful completion, the snprintf() function shall return the number of bytes that would be written to s had n been sufficiently large excluding the terminating null byte. So it seems return value of 6 corresponds to posix expectation. > > code: > #include <stdio.h> > int main() { > wchar_t buf[2]; > int len = snwprintf(buf, sizeof(buf) / 2, L"world!"); > printf("%d\n", len); > } > > > Thanks. > > ------------------------------------------------------------------------------ Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ _______________________________________________ Mingw-w64-public mailing list Mingw-w64-public@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/mingw-w64-public
