On Thu, Apr 28, 2016 at 11:21 AM, Connor Abbott <[email protected]> wrote: > On Thu, Apr 28, 2016 at 11:20 AM, Ilia Mirkin <[email protected]> wrote: >> What if the existing operations were already exact? > > They aren't -- the builder makes them non-exact by default, and we > initialize the builder ourselves in this pass.
Hmmmmmm... OK. I'm just thinking of the case precise c = op(a, b) And op gets lowered. The resulting operations should also be exact. If that's what's happening, then all's well. -ilia _______________________________________________ mesa-dev mailing list [email protected] https://lists.freedesktop.org/mailman/listinfo/mesa-dev
