| Issue |
144829
|
| Summary |
[libc++] `std::locale(named, unnamed, std::locale::none)` should obtain its name from `named`
|
| Labels |
libc++
|
| Assignees |
|
| Reporter |
cpplearner
|
Reduced from [`libcxx/test/std/localization/locales/locale/locale.cons/name_construction.pass.cpp`](https://github.com/llvm/llvm-project/blob/351303c28e8feb85c93d8e9480f534653b032735/libcxx/test/std/localization/locales/locale/locale.cons/name_construction.pass.cpp):
```c++
#include <iostream>
#include <locale>
constexpr auto LOCALE_en_US_UTF_8 = "en_US.UTF-8";
int main(int, char**) {
std::locale en(LOCALE_en_US_UTF_8);
std::locale unnamed(std::locale(), new std::ctype<char>);
{
std::locale loc(en, unnamed, std::locale::none);
std::cout << loc.name() << '\n';
}
return 0;
}
```
Both libstdc++ and MSVC's STL print "en_US.UTF-8" for `loc.name()`, but libc++ prints "*".
I think this can be fixed by swapping the two conditions in `build_name`.
https://github.com/llvm/llvm-project/blob/351303c28e8feb85c93d8e9480f534653b032735/libcxx/src/locale.cpp#L101-L110
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