I have a very simple lldb script:
thread select 1
disassemble --start-address $pc-24 --end-address $pc+24
When I run lldb with -o "process launch -s" and -s "dis.lldb", I get odd output
- the disassembly from "thread select 1" and from the disassemble command run
together.
This is what I see with top-of-tree on Ubuntu 16:
bin/lldb /bin/ls -o "process launch -s" -s dis.lldb
(lldb) target create "/bin/ls"
Current executable set to '/bin/ls' (x86_64).
(lldb) process launch -s
Process 32258 launched: '/bin/ls' (x86_64)
(lldb) command source -s 0 'dis.lldb'
Executing commands in '/local/mnt/ted/tip/full/dis.lldb'.
(lldb) thread select 1
(lldb) disassemble --start-address $pc-24 --end-address $pc+24
* thread #1, name = 'ls', stop reason = signal SIGSTOP
frame #0: 0x00007ffff7dd7c30 ld-2.23.so`_start
ld-2.23.so`_start:
-> 0x7ffff7dd7c30 <+0>: movq %rsp, %rdi
0x7ffff7dd7c33 <+3>: callq 0x7ffff7dd89b0 ; _dl_start at
rtld.c:353
ld-2.23.so`_dl_start_user:
0x7ffff7dd7c38 <+0>: movq %rax, %r12
0x7ffff7dd7c3b <+3>: movl 0x225037(%rip), %eax ; _dl_skip_args
ld-2.23.so`oom:
0x7ffff7dd7c18 <+13>: xorl %eax, %eax
0x7ffff7dd7c1a <+15>: callq 0x7ffff7de88f0 ; _dl_dprintf at
dl-misc.c:275
0x7ffff7dd7c1f <+20>: movl $0x7f, %edi
0x7ffff7dd7c24 <+25>: callq 0x7ffff7df24f0 ; __GI__exit at
_exit.c:27
0x7ffff7dd7c29: nopl (%rax)
ld-2.23.so`_start:
-> 0x7ffff7dd7c30 <+0>: movq %rsp, %rdi
0x7ffff7dd7c33 <+3>: callq 0x7ffff7dd89b0 ; _dl_start at
rtld.c:353
ld-2.23.so`_dl_start_user:
0x7ffff7dd7c38 <+0>: movq %rax, %r12
0x7ffff7dd7c3b <+3>: movl 0x225037(%rip), %eax ; _dl_skip_args
0x7ffff7dd7c41 <+9>: popq %rdx
0x7ffff7dd7c42 <+10>: leaq (%rsp,%rax,8), %rsp
0x7ffff7dd7c46 <+14>: subl %eax, %edx
(lldb)
Note that the address goes from c3b to c18 right after ld-2.23.so`oom.
How can I separate the outputs of thread select and disassemble? If I stick in
something like "register read pc" in between the thread select and the dis, I
get the output from it before the output from the thread select and dis.
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