mgorny added a comment.
I suppose you need to make the timeout branch entirely separate from the
non-timeout branch, as the variable assignment does not take place then.
================
Comment at: lldb/test/API/lldbtest.py:100
+ output = """Script:\n--\n%s\n--\nExit Code: %d\n""" % (
+ ' '.join(cmd), exitCode)
+ if timeoutInfo is not None:
----------------
This crashes on timeout since `exitCode` is not declared:
```
UNRESOLVED: lldb-api :: tools/lldb-vscode/variables/TestVSCode_variables.py
(1906 of 1907)
******************** TEST 'lldb-api ::
tools/lldb-vscode/variables/TestVSCode_variables.py' FAILED ********************
Exception during script execution:
Traceback (most recent call last):
File "/home/mgorny/llvm-project/llvm/utils/lit/lit/worker.py", line 91, in
_execute_test_handle_errors
return _adapt_result(test.config.test_format.execute(test, lit_config))
File "/home/mgorny/llvm-project/llvm/tools/lldb/test/API/lldbtest.py", line
100, in execute
' '.join(cmd), exitCode)
UnboundLocalError: local variable 'exitCode' referenced before assignment
```
================
Comment at: lldb/test/API/lldbtest.py:105
+
+ if out:
+ output += """Command Output (stdout):\n--\n%s\n--\n""" % (out,)
----------------
I suppose this will crash as well, and below.
Repository:
rG LLVM Github Monorepo
CHANGES SINCE LAST ACTION
https://reviews.llvm.org/D73384/new/
https://reviews.llvm.org/D73384
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