================ @@ -800,16 +800,24 @@ Print the dynamic type of the result of an expression (gdb) p someCPPObjectPtrOrReference (Only works for C++ objects) +LLDB does this automatically if determining the dynamic type does not require +running the target (in C++, running the target is never needed). This default is +controlled by the `target.prefer-dynamic-value` setting. If that is disabled, it +can be re-enabled on a per-command basis: + .. code-block:: shell - (lldb) expr -d 1 -- [SomeClass returnAnObject] - (lldb) expr -d 1 -- someCPPObjectPtrOrReference + (lldb) settings set target.prefer-dynamic-value no-dynamic-values + (lldb) frame variable -d no-run-target someCPPObjectPtrOrReference + (lldb) expr -d no-run-target -- someCPPObjectPtr -or set dynamic type printing to be the default: +Note that printing of the dynamic type of references is not possible with the +`expr` command. The workaround is to take the address of the reference and +instruct lldb to print the children of the resulting pointer. ---------------- labath wrote:
(If you're wondering why we're making a copy of a reference -- but not of a pointer -- I suspect that's because in the expression evaluator we do not differentiate between an object and a reference to it. I suppose we could do it, and then somehow treat references as pointers, but I don't exactly know what would that entail.) https://github.com/llvm/llvm-project/pull/138538 _______________________________________________ lldb-commits mailing list lldb-commits@lists.llvm.org https://lists.llvm.org/cgi-bin/mailman/listinfo/lldb-commits
