> Can you please explain what happens when a packet is being delayed? I seem to > understand that each packet has a life time and it gets discarded when its > time is up. Does lives555 wait for the following packets to arrive, or does > it continue delivering packets to client and then deliver the previous > packets (out of order?).
Our "RTPSource" class (and subclasses) *always* delivers (the payload of) incoming RTP packets in order. In other words, data is *never* delivered out-of-order, even if incoming RTP packets happen to be misordered. If there is no packet loss - or misordering - in the network, then our code always delivers (the payload of) incoming RTP packets without delay. I.e., if the last-received RTP packet had RTP sequence number N, and the next incoming packet has RTP sequence number N+1 (mod 65536), then this next incoming packet is always delivered immediately. If, however, the next incoming packet has RTP sequence number N+2 (or later), then its payload is not delivered immediately. Instead, it is delayed by the 'packet reordering threshold', to see what subsequent packets happen to arrive. If packet N+1 arrives before the 'packet reordering threshold' time, then it will then get delivered, followed by (the already-arrived) packet N+2. If, however, the 'packet reordering threshold' threshold elapses without packet N+1 arriving, then (the already-arrived) packet N+2 will get delivered instead. In this case, packet N+1 will never get delivered, even if it happens to arrive later. By default, the 'packet reordering threshold' is 100 ms. Therefore, incoming packets may be delayed by this time - but *only* if there is packet loss in the network. It's important to understand that this is the *only* place in our code where incoming packets may be delayed before being delivered. If you are seeing delays greater than 100ms, then it is *not* happening in our code, so don't waste your time looking for it there. Ross Finlayson Live Networks, Inc. http://www.live555.com/
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