>> complains about the following statement:
>> ----
>> result = *(float*)&resultAsUnsigned;
No, this compiler warning message does not indicate a bug in the code.
"resultAsUnsigned" is a 4-byte value that stores a 'float'; it is not an
unsigned value that gets converted to a float.
>> This little snippet, and it's compiled output, illustrate the problem:
No, a more accurate 'snippet', which illustrates what the code really does,
would be:
void func(float &f)
{
float val = 3.0;
unsigned *vptr = (unsigned*)&val;
unsigned resultAsUnsigned = *vptr; // a 4-byte value that stores a 'float'
f = *(float*)&resultAsUnsigned;
}
(and then "main()" as you originally wrote it)
If you can suggest an alternative coding that eliminates your compiler warning,
then that would be great. But the code - as it stands - is not in error.
Ross Finlayson
Live Networks, Inc.
http://www.live555.com/
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