Didier Kryn a écrit :
Konstantin, I reproduced your ioctl() problem with the attached
program. The conclusion is that the only valid size and base parameters
for A16 are windowSizeL=0x10000 and xlatedAddrL=0. This means the A16
space can only be mapped as a whole. What you observed with
xlatedAddrL=0x10100000 is that the ioctl(), gently masks the irrelevant
high order bits.
Best regards.
Didier
Oops! I forgot the attachment...
#include <linux/stddef.h>
#include <stdio.h>
#include <errno.h>
#include <string.h>
#include <sys/ioctl.h>
#include <unistd.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <sys/mman.h>
#include "vmedrv.h"
#if !defined(offsetof)
/* maybe defined (if <linux/stddef.h> included indirectly) */
# define offsetof(TYPE, MEMBER) ((size_t) &((TYPE *)0)->MEMBER)
#endif
int main(void)
{
int vmepd, i;
char *devname="/dev/vme/vme_out0";
vmeOutWindowCfg_t a16d16 = {0,1,0,0,0,0x1000000,0,0,0,0,0,0,VME_SSTNONE,
VME_A16,VME_D16,VME_SCT,VME_SUPER,VME_DATA,0};
unsigned size_max=0x10000;
unsigned base, size;
unsigned short *vmebus;
vmepd = open(devname, O_RDWR);
if(vmepd==-1)
{
perror(devname);
return 1;
}
for( base=0 ; (size = size_max - base) ; base+=0x100 )
{
a16d16.xlatedAddrL = base;
a16d16.windowSizeL = size;
if(ioctl(vmepd, VME_IOCTL_SET_OUTBOUND, &a16d16))
printf("ioctl failed for base %x, size %x: %s\n", base, size, strerror(errno));
else
printf("ioctl OK for base %x, size %x\n", base, size);
}
for( base=0, size=0x100 ; size <= size_max ; size+=0x100 )
{
a16d16.xlatedAddrL = base;
a16d16.windowSizeL = size;
if(ioctl(vmepd, VME_IOCTL_SET_OUTBOUND, &a16d16))
printf("ioctl failed for base %x, size %x: %s\n", base, size, strerror(errno));
else
printf("ioctl OK for base %x, size %x\n", base, size);
}
close(vmepd);
}
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