Hi Mike,
On Wed, Jan 16, 2019 at 03:44:12PM +0200, Mike Rapoport wrote:
> The last parameter of memblock_alloc_from() is the lower limit for the
> memory allocation. When it is 0, the call is equivalent to
> memblock_alloc().
>
> Signed-off-by: Mike Rapoport <r...@linux.ibm.com>
Acked-by: Paul Burton <paul.bur...@mips.com> # MIPS part
Thanks,
Paul
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