find_idlest_group_cpu goes through CPUs of a group previous selected by find_idlest_group. find_idlest_group returns NULL if the local group is the selected one and doesn't execute find_idlest_group_cpu if the group to which 'cpu' belongs to is chosen. So we're always guaranteed to call find_idlest_group_cpu with a group to which cpu is non-local. This makes one of the conditions in find_idlest_group_cpu an impossible one, which we can get rid off.
Reviewed-by: Brendan Jackman <[email protected]> Reviewed-by: Vincent Guittot <[email protected]> Signed-off-by: Joel Fernandes <[email protected]> --- kernel/sched/fair.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c index 1b10821d8380..44407e703b5f 100644 --- a/kernel/sched/fair.c +++ b/kernel/sched/fair.c @@ -5948,7 +5948,7 @@ find_idlest_group_cpu(struct sched_group *group, struct task_struct *p, int this } } else if (shallowest_idle_cpu == -1) { load = weighted_cpuload(cpu_rq(i)); - if (load < min_load || (load == min_load && i == this_cpu)) { + if (load < min_load) { min_load = load; least_loaded_cpu = i; } -- 2.15.1.504.g5279b80103-goog
