On Wed, Apr 22, 2015 at 02:44:08PM +0200, Stephan Mueller wrote: > > > Where does this 8-byte alignment requirement come from? > > Well, I am accessing the data in 8-byte chunks. Moreover, in the scatterwalk > copy functions, I search through the scatterlists in 8 byte increments. If, > say, a scatterwalk is not a multiple of 8 bytes, the scatterwalk logic will > not process the last chunk of memory.
Alignment refers to whether the address can handle a load of a given size by the CPU, it does not mean that the length will be a multiple of the alignment. Alignment is only required if you do a load of the given size. For example if you read a u64 then on many architectures that will require an alignment of 8. Vice versa if you only do byte loads then you do not need to specify the alignment. I don't see any u64 loads in your code. Cheers, -- Email: Herbert Xu <herb...@gondor.apana.org.au> Home Page: http://gondor.apana.org.au/~herbert/ PGP Key: http://gondor.apana.org.au/~herbert/pubkey.txt -- To unsubscribe from this list: send the line "unsubscribe linux-crypto" in the body of a message to majord...@vger.kernel.org More majordomo info at http://vger.kernel.org/majordomo-info.html
