On Fri, 2012-09-28 at 14:17 +0200, Noel Grandin wrote:
> you can do this:
>
> void f(OUString s) {
> s = "2";
> }
>
> OUString s = "1";
> f(s);
> cout << s; // will print "2"
That will print "1" not "2".
Maybe you meant
void f(OUString& s) {
s = "2";
}
OUString s = "1";
f(s);
cout << s; // will print "2"
but that's perfectly reasonable.
C.
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