Thomas Trepl wrote:
Hi all,shouldn't the instruction (6.9. Glibc-2.25) case $(uname -m) in x86) GCC_INCDIR=/usr/lib/gcc/x86-pc-linux-gnu/7.1.0/include ln -s ld-linux.so.2 /lib/ld-lsb.so.3 ;; x86_64) GCC_INCDIR=/usr/lib/gcc/x86_64-pc-linux-gnu/7.1.0/include ln -s ../lib/ld-linux-x86-64.so.2 /lib64 ln -s ../lib/ld-linux-x86-64.so.2 /lib64/ld-lsb-x86-64.so.3 ;; esac read like case $(uname -m) in i?86) GCC_INCDIR=/usr/lib/gcc/$(uname -m)-pc-linux-gnu/7.1.0/include ...
No. The kernel does not differentiate between 32-bit x86 processors in its machine name.
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