>>>>> Lifepillar <[email protected]> writes: > But John's reply in fact makes me wonder: I have always assumed that > Ledger's computations are exact (as in ³multiple-precision arithmetic²). Is > that not the case?
They are exact because they are rational numbers, i.e., always some p/q. They are rendered as floating-point only at display time. So it is not possible to lose anything during rounding, as no rounding happens except to display amounts to the user. John
