https://bugs.kde.org/show_bug.cgi?id=397313
--- Comment #3 from Daniel Fahlgren <dan...@fahlgren.se> ---
Just to clarify. The following example shows that long double ld1 = <value>
does not work as you normally expect an assignment to work.
#include <stdio.h>
#include <string.h>
void func1(void)
{
long double a;
memset(&a, 0xFF, sizeof a);
}
void func2(void)
{
long double a = 0;
char *p = (char *) &a;
for (int i = 0; i < sizeof a; i++)
printf("%d: 0x%02x\n", i, p[i] & 0xff);
}
int main(int argc, char *argv[])
{
func1()
func2();
return 0;
}
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