It seems that the way Julia handles A[1,:] changed in v0.5. *julia> **A = [1 2 3; 4 5 6]*
*2×3 Array{Int64,2}:*
* 1 2 3*
* 4 5 6*
*julia> **A[1,:]*
*3-element Array{Int64,1}:*
* 1*
* 2*
* 3*
*julia> **size(A[1,:])*
*(3,)*
A[1,:] used to be a row-vector in v0.4 same as in MATLAB, but it is now a
column vector. What is the *best and most reasonable* way to retrieve rows
of a matrix as a row vector? Just transpose it like A[1,:]' ?
