jackskmok opened a new issue, #9116:
URL: https://github.com/apache/iceberg/issues/9116
I am trying to testing the create branch feature with the table with AWS
Glue catalog , but hit the error as title. Here is the message:
>>> spark.sql("alter table iceberg.athena_data create branch 'testing'");
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File
"/opt/homebrew/Cellar/apache-spark/3.5.0/libexec/python/pyspark/sql/session.py",
line 1631, in sql
return DataFrame(self._jsparkSession.sql(sqlQuery, litArgs), self)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File
"/opt/homebrew/Cellar/apache-spark/3.5.0/libexec/python/lib/py4j-0.10.9.7-src.zip/py4j/java_gateway.py",
line 1322, in __call__
File
"/opt/homebrew/Cellar/apache-spark/3.5.0/libexec/python/pyspark/errors/exceptions/captured.py",
line 185, in deco
raise converted from None
pyspark.errors.exceptions.captured.ParseException:
[PARSE_SYNTAX_ERROR] Syntax error at or near 'create'.(line 1, pos 32)
== SQL ==
alter table iceberg.athena_data create branch 'testing'
--------------------------------^^^
Spark Version is 3.5
Execution Command :
export AWS_PROFILE=lfdba
spark-sql --packages
org.apache.iceberg:iceberg-spark-runtime-3.4_2.12:1.4.1,org.apache.iceberg:iceberg-aws-bundle:1.4.1
\
--conf spark.sql.defaultCatalog=my_catalog \
--conf
spark.sql.catalog.my_catalog=org.apache.iceberg.spark.SparkCatalog \
--conf
spark.sql.catalog.my_catalog.warehouse=s3://testingbucket/lficeberg/ \
--conf
spark.sql.catalog.my_catalog.catalog-impl=org.apache.iceberg.aws.glue.GlueCatalog
\
--conf
spark.sql.catalog.my_catalog.io-impl=org.apache.iceberg.aws.s3.S3FileIO \
Reference : https://iceberg.apache.org/docs/latest/getting-started/
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