On Tuesday, 7 March 2023 21:20:02 PST Hamish Moffatt via Interest wrote: > I confirm that my test code compiles in 6.5.0-beta3.
And I can reproduce the error with GCC 13 if I check out the 6.4.2 headers. GCC 13 says: note: candidate: ‘template<class T> QDebugIfHasDebugStreamContainer<QList<T>, T> operator<<(QDebug, const QList<T>&)’ note: template argument deduction/substitution failed qdebug.h:217:53: required by substitution of ‘template<class T> QDebugIfHasDebugStreamContainer<QList<T>, T> operator<<(QDebug, const QList<T>&) [with T = QString]’ type_traits:2594:11: error: no type named ‘type’ in ‘struct std::enable_if<false, QDebug>’ This is GCC speak for "condition evaluated to false" By moving the constraint from the return type to a static_assert inside the function, I can prove that the ostream test fails: qdebug.h:219:5: error: static assertion failed due to requirement 'QTypeTraits::has_ostream_operator_v<QDebug, QString>' But that test is: std::void_t<decltype(detail::reference<Stream>() << detail::const_reference<T>())> and if I copy that expression to the function, it does compile. Moreover, the changes to qdebug.h and qtypeinfo.h don't seem related. So I have no clue *why* the check fails and *how* it was fixed. This is template black magic. It works right now and I've spent enough time investigating. -- Thiago Macieira - thiago.macieira (AT) intel.com Cloud Software Architect - Intel DCAI Cloud Engineering
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