Il 15/06/20 03:26, Nicholas Yue ha scritto:
The return widget object does not have a viewport() method from looking
at the QWidget - docs <https://doc.qt.io/qt-5/qwidget.html>
void AttributeItem::mousePressEvent(QGraphicsSceneMouseEvent* event)
{
if (event->button()==Qt::LeftButton)
{
QWidget *w = event->widget();
} else
QGraphicsItem::mousePressEvent(event);
}
Sorry, what I meant is the other way around: the widget returned *is* the viewport() of your QGraphicsView. (So, typically, getting the parent widget of that widget will give you QGV you're looking for.)
HTH, -- Giuseppe D'Angelo | giuseppe.dang...@kdab.com | Senior Software Engineer KDAB (France) S.A.S., a KDAB Group company Tel. France +33 (0)4 90 84 08 53, http://www.kdab.com KDAB - The Qt, C++ and OpenGL Experts
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