Let's see if the formatting is any better this time...
Below is my progress thus far. I've created a simple app with two
QPlainTextEdit's. The only thing else it does is to print out the name
of the keyboard input source associated with a QPlainTextEdit when you
click into it. I'm unsure how to translate the python code for changing
the keyboard into C++ but I've added comments to the
"MainWindow::changeKeyboard" method below to show my approach in python.
Any help or suggestions would be most welcome.
Best regards,
Tim
mainwindow.h:
#ifndef MAINWINDOW_H
#define MAINWINDOW_H
#include <QMainWindow>
#include <QPlainTextEdit>
class MainWindow : public QMainWindow
{
Q_OBJECT
public:
MainWindow();
void changeKeyboard(QVariant keyboard);
protected:
bool eventFilter(QObject *obj, QEvent *event);
private:
QWidget *mainWidget;
QPlainTextEdit *textEdit1;
QPlainTextEdit *textEdit2;
};
#endif // MAINWINDOW_H
mainwindow.cpp:
#include <QWidget>
#include <QVBoxLayout>
#include <QPlainTextEdit>
#include <QObject>
#include <QEvent>
#include <QDebug>
#include "mainwindow.h"
#include "Windows.h"
MainWindow::MainWindow()
{
mainWidget = new QWidget;
setCentralWidget(mainWidget);
QVBoxLayout *layout = new QVBoxLayout;
textEdit1 = new QPlainTextEdit;
textEdit1->setProperty("keyboard", 0x00000809); // British(Windows)
textEdit2 = new QPlainTextEdit;
textEdit2->setProperty("keyboard", 0x00010C00); // Myanmar(Windows)
layout->addWidget(textEdit1);
layout->addWidget(textEdit2);
mainWidget->setLayout(layout);
textEdit1->installEventFilter(this);
textEdit2->installEventFilter(this);
}
bool MainWindow::eventFilter(QObject *obj, QEvent *event)
{
if (obj == textEdit1 || obj == textEdit2) {
if (event->type() == QEvent::FocusIn) {
changeKeyboard(obj->property("keyboard"));
}
}
return QMainWindow::eventFilter(obj, event);
}
void MainWindow::changeKeyboard(QVariant keyboard)
{
qDebug() << keyboard.toString();
/* The following is how I did this in Python but I am unsure how to
translate this into C++.
A different approach in C++ would be okay, but it needs to be an
approach I can translate
back into Python/PyQt.
from Cocoa import NSTextInputContext //This line goes at top of
page with any other import statements
ic = NSTextInputContext.currentInputContext()
if not ic:
ic = NSTextInputContext.new()
ic.setValue_forKey_(keyboard.toString(), 'selectedKeyboardInputSource')
*/
}
On 19/08/2016 16:48, timur.kris...@gmail.com wrote:
Can you create a simple example app without Python, to see if it really is Qt's
fault?
(Just create an app with Qt Creator and run it. As far as I understand, you use
QWidgets, right? If so, create an empty QWitgets project, run and see how it
goes.)
On Fri Aug 19 13:33:58 2016 GMT+0200, Timothy W. Grove wrote:
Changing the keyboard input source on OS X back and forth between
'British' and 'Myanmar-QWERTY' crashes my PyQt v5.7 application after
about three changes, usually corrupting an attached sqlite database as
well. 'Myanmar-QWERTY' is the only input source that I'm having trouble
with; all others that I've tested so far appear okay. The windows
version of the application also seems okay. My application is fairly
complex, but I'm seeing this issue even with an absolute minimal app
containing only one window. I'm not certain if the issue is with PyQt or
Qt or the input source itself, but it doesn't appear to be with python
as a Tkinter app worked okay.
Any answers would be great, but if anyone could suggest where to find a
solution that would also be helpful. This is a pretty obscure bug, but
finding a solution or work-around is important to the application I'm
developing. Thank you.
Best regards,
Timothy Grove
Test program:
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
import sys
from PyQt5.QtWidgets import QMainWindow
from PyQt5.QtWidgets import QTextEdit
from PyQt5.QtWidgets import QApplication
class MainWindow(QMainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
text = QTextEdit()
self.setCentralWidget(text)
if __name__ == "__main__":
app = QApplication(sys.argv)
mw = MainWindow()
mw.show()
sys.exit(app.exec_())
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