Il 27/03/2013 11:57, Sensei ha scritto: > I assume that "nothing" isn't a valid boundary here. > > Am I right?
No, you're just falling into a very common error when using \b. \b matches the 0-length transition between a \w character and a \W, and the beginning and the end of the string are counted as a \W. But there's no such transition in your string: the \b is between the beginning (\W) and the leading backslash (\W again). Therefore, it will not match. HTH, -- Giuseppe D'Angelo | giuseppe.dang...@kdab.com | Software Engineer KDAB (UK) Ltd., a KDAB Group company Tel. UK +44-1738-450410, Sweden (HQ) +46-563-540090 KDAB - Qt Experts - Platform-independent software solutions _______________________________________________ Interest mailing list Interest@qt-project.org http://lists.qt-project.org/mailman/listinfo/interest
