Geoff Hutchison writes:
> On Tue, 8 Feb 2000 [EMAIL PROTECTED] wrote:
>
> > > given that rest is char * and not const char *? What will (String) =
> > > (char *) default to?
> >
> > No it's not. The opposite would be, barking when (String) = (const char*).
>
> Uhm. I hope I'm not the only one confused by your statement Loic. Are you
> saying that this code should be OK?
No, I did not look at it. I was just saying that operator = (const char*)
was good for (char*) assignement. Sorry for the terse response :-} Here is
what I meant:
/*
[loic@localhost tmp]$ g++ -Wall -o /tmp/a /tmp/a.C
/tmp/a.C: In function `int main()':
/tmp/a.C:39: passing `const char *' as argument 1 of `t1::operator =(char *)' discards
qualifiers
[loic@localhost tmp]$ /tmp/a
t1:char*
t1:char*
t2:const char*
t2:const char*
t3:const char*
t3:char*
[loic@localhost tmp]$
*/
#include <iostream.h>
class t1 {
public:
void operator = (char* foo) { cerr << "t1:char*" << endl; }
};
class t2 {
public:
void operator = (const char* foo) { cerr << "t2:const char*" << endl; }
};
class t3 {
public:
void operator = (char* foo) { cerr << "t3:char*" << endl; }
void operator = (const char* foo) { cerr << "t3:const char*" << endl; }
};
int main()
{
const char* vconst = "foo";
char* v = "bar";
t1 v1;
v1 = vconst;
v1 = v;
t2 v2;
v2 = vconst;
v2 = v;
t3 v3;
v3 = vconst;
v3 = v;
}
--
Loic Dachary
24 av Secretan
75019 Paris
Tel: 33 1 42 45 09 16
e-mail: [EMAIL PROTECTED]
URL: http://www.senga.org/
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