On Wed, Oct 7, 2009 at 12:08 PM, Ben Franksen <[email protected]> wrote:
>
> More generally, any ring with multiplicative unit (let's call it 'one') will
> do.

Isn't that every ring? As I understand it, the multiplication in a
ring is required to form a monoid.

-- 
Dave Menendez <[email protected]>
<http://www.eyrie.org/~zednenem/>
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