On Mon, May 18, 2009 at 10:02 PM, Ryan Ingram <[email protected]> wrote: > Unfortunately, you can't derive Show on Chain as defined, because it > contains a function:
Sure you can. I just tried the following, and it compiled without complaints. > import Text.Show.Functions > > data Chain = Link Int (Int -> Chain) deriving (Show) The usual warnings about orphan instances apply, but the purpose of the Text.Show.Functions module is to provide a standard Show instance for functions so that libraries (e.g., QuickCheck) don't declare conflicting instances. -- Dave Menendez <[email protected]> <http://www.eyrie.org/~zednenem/> _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
