On Sun, Dec 21, 2008 at 10:28 AM, Maurício <[email protected]> wrote:
> Hi,
>
> Why isn't the last line of this code allowed?
>
> f :: (TestClass a) => a -> Integer
> f = const 1
> a = (f,f)
> g = fst a
>
> The only thing I can think about is monomorphism
> restriction, but it's allowed (or even the third
> line would not be accepted). Is there something
> I could read to understand that?
>
> Thanks,
> Maurício
>
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>
The monomorphism restriction refuses to accept the definition of a.
However, even if we turn the monomorphism restriction off there is
still a problem.
> {-# LANGUAGE NoMonomorphismRestriction #-}
>
> f :: (TestClass a) => a -> Integer
> f = const 1
> a = (f,f)
> g = fst a
In this case, the definition of a is accepted, but not the definition
of g. The reason is that a has type
a :: (TestClass a, TestClass b) => (a,b)
and then when we take 'fst' of this value (as in g) we get
g :: (TestClass a, TestClass b) => a
which is an ambiguous type, since there is no way to tell the compiler
what 'b' is when running g.
Cheers,
Reiner
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