On Tue, 22 May 2007, Greg Meredith wrote: > mSplitC :: [a] -> [([a], [a])] -- C for comprehension > > mSplitC [] = [([],[])] > mSplitC [x] = [([x],[])] > mSplitC (x:xs) = concat [ [(x:l,r),(l,x:r)] | (l,r) <- mSplitC xs ] > > which Matthias Radestock suggested to me. > > Note that if you only supply the empty multiset case, then you end up with > duplicates.
That is ([1,2],[3]) and ([3],[1,2]) are considered the same? But you need always pairs not only [1,2] and [3] ? _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
