If I'm reading your question correctly, you're looking for path.up() and
path.down() to change levels in the tree, and path.next() and
path.prev() to change nodes within a level. Continuing your example and
assuming iter points to row 3,
cout << path.to_string() << endl; // 3
path.down();
cout << path.to_string() << endl; // 3:0
path.next();
cout << path.to_string() << endl; // 3:1
path.down();
cout << path.to_string() << endl; // 3:1:0
...
On 2016/06/28 09:22, Kamalpreet Grewal wrote:
Hi
I have been trying to get the index value of rows in a treeview. I did it using:
path = _tree.get_model()->get_path(iter);
int i = atoi(path.to_string().c_str());
This works well by storing selected row's index in 'i'. Next I have
children in these rows and I wish to get the index of the child of a
row selected.
And I came across: http://scentric.net/tutorial/sec-treemodel-rowref.html
How the indexes are assigned at different depths in a treeview is
well-explained at this link in the beginning only.
Obtaining these indexes in the form "0:1" etc has been an issue for
me. How can this be done? Are there any alternatives to get indexes of
children of rows?
Thanks in advance.
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