On Sat, Jun 28, 2025, Tadziu Hoffmann wrote: > > > However, if one enters an arithmetic expression instead of a > > digit, \v behaves as if 'u' is the default scaling unit. > > [...] > > \v'-24000/2' > > I think the behavior is correct. Any numbers that don't have > a scaling factor will get the default scaling factor, and the > resulting value is interpreted as units: > > 1 = 1v = 12000u > 12p = 12000u > 24000/2 = 24000v/2v = 288000000u/24000u = 12000u
Makes sense. Thanks, Tadziu. -- Peter Schaffter https://www.schaffter.ca
