I regard the following behaviour of grog, which has been there
from the beginning, to be wrong:

On the input files
a.n:
.EQ
.so /dev/null
.EN

b.n:
.so a.n

the following commands give the indicated results:
grog a.n: groff a.n     [missing -se]
grog b.n: groff b.n     [missing -se]

With the shell version of grog the results are:
grog a.n: groff -e a.   [missing -s]
grog b.n: groff -se b.n [correct]

Do people agree?  I find it a nuisance as I frequently generate the
contents of tables and other things by an external means.

I've sent a simple patch of the shell version.

Denis





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