> so the 2D solutions will be > close to correct You'd have to define what you would call a "correct" 3D solution. Imagine a circle drawn on a sphere with a point marked within it. Is the point inside the circle or not from your viewpoint? It is above the plane of the circle, so could be considered to be 'outside' in 3D terms. In spherical geometry (which is indeed 2D) it would be considered inside, as we are only interested in the surface of the sphere.
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