On Mon, Apr 22, 2024 at 2:25 PM Jochen Voss <[email protected]> wrote:
>
> Using generics, can I somehow write a constraint which says that *T (instead
> of T) implements a certain interface? The following code illustrated what
> I'm trying to do:
>
> type A int
>
> func (a *A) Set(x int) {
> *a = A(x)
> }
>
> type B string
>
> func (b *B) Set(x int) {
> *b = B(strconv.Itoa(x))
> }
>
> type C1 struct {
> Val []A
> }
>
> func (c *C1) Set(v int) {
> for i := range c.Val {
> c.Val[i].Set(v)
> }
> }
>
> type C2 struct {
> Val []B
> }
>
> func (c *C2) Set(v int) {
> for i := range c.Val {
> c.Val[i].Set(v)
> }
> }
>
> I would like to use generics to use a single definition for the methods which
> here are func (c *C1) Set(v int) and func (c *C2) Set(v int). (My real code
> has many base types, instead of just A and B.) How can I do this?
>
> I tried the naive approach:
>
> type C[T interface{ Set(int) }] struct {
> Val []T
> }
>
> but when I try to use the type C[A] now, I get the error message "A does not
> satisfy interface{Set(int)} (method Set has pointer receiver)".
type C[P interface {
*E
Set(int)
}, E any] struct {
Val []P
}
Ian
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