That's a well-known implementation restriction, mentioned in the release
notes of Go 1.18 <https://go.dev/doc/go1.18#generics>:

The Go compiler only supports calling a method m on a value x of type
> parameter type P if m is explicitly declared by P's constraint interface.
> Similarly, method values x.m and method expressions P.m also are only
> supported if m is explicitly declared by P, even though m might be in the
> method set of P by virtue of the fact that all types in P implement m. We
> hope to remove this restriction in a future release.


So far, we haven't managed to remove this restriction. It's surprisingly
complicated.
I tend to spell that call as `P(&t).Bar()` for what it's worth.

On Wed, May 3, 2023 at 5:48 PM Steve Heyns <[email protected]> wrote:

> Ran into this and I was wondering if it was a bug or not. Assuming "Foo"
> is an interface with a function of "Bar", then the following function
> should have a type reference of T and a pointer reference of P that
> implements the Foo interface, and is bound to the Type of T (
> https://gotipplay.golang.org/p/BKsA7-6MlHV).
>
> *type  Foo interface {*
>
> * Bar() string }*
>
>
>
>
> *func Update[T any, P interface { Foo *T}]() {*
>
> Inside that function :
> *var t T; t.Bar()* // gives
> t.Bar undefined (type T has no field or method Bar)
>
> *var t T; i:= &t; i.Bar()* // Gives
> i.Bar undefined (type *T is pointer to type parameter, not type parameter)
>
> But the following passes compile, and creates a new instance of type T,
> with "i" being the pointer to it.
> *var t T; var i P; i= &t; i.Bar()* // Pass
>
> IMO all three ways should work, but curious as to why they don't
>
> Thanks
> Nz
>
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