On Sun, May 23, 2021 at 11:02 AM [email protected] <[email protected]>
wrote:
> And how to interpret the conflicting messages for the following program?
>
In one case, `g` is inlined, which is sufficient to prove that its return
does not escape. But if you only analyse `g` as-is, you must assume that
the return has to escape, as you don't know what the caller would do with
is.
>
> package main
>
> type T int
>
> const N = 1<<12
> var i = N - 1
>
> func main() {
> var r = make([]T, N) // make([]T, N) does not escape
> println(r[i])
>
> var r1 = g() // make([]T, N) does not escape
> println(r1[i])
>
> }
>
> func g() []T {
> var ts = make([]T, N) // make([]T, N) escapes to heap
> return ts
> }
>
> On Sunday, May 23, 2021 at 4:51:30 AM UTC-4 [email protected] wrote:
>
>> In the following code, "make([]T, n)" is reported as escaped.
>> But does it really always escape at run time?
>> Does the report just mean "make([]T, n) possibly escapes to heap"?
>>
>> package main
>>
>> type T int
>>
>> const K = 1<<13
>> const N = 1<<12
>> var n = N
>> var i = n-1
>>
>> func main() {
>> var r = make([]T, N) // make([]T, N) does not escape
>> println(r[i])
>>
>> var r2 = make([]T, n) // make([]T, n) escapes to heap
>> println(r2[i])
>>
>> var r3 = make([]T, K) // make([]T, K) escapes to heap
>> println(r3[i])
>> }
>>
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