Hi,
If I set Body to the out file itself, an item with the name of the outfile
is uploaded to the S3 bucket, but that item is 0 bytes in size and when I
click on it in S3 it doesn't appear, whereas with the buffer stuff, the
image size in bytes is correct, but a black square shows up. This is how I
get the out file in the first place:
file, header, err := r.FormFile("upload")
if err != nil {
fmt.Fprintln(w, err)
return
}
defer file.Close()
out, err := os.Create("/path/to/file/" + header.Filename)
if err != nil {
fmt.Fprintf(w, "Unable to create the file for writing. Check your write
access privilege")
return
}
defer out.Close()
_, err = io.Copy(out, file)
if err != nil {
fmt.Fprintln(w, err)
}
I'm not sure why setting Body to the out file itself results in a 0 byte
upload. Is there another way to upload the image to s3?
Thanks
On Tuesday, August 14, 2018 at 6:42:50 AM UTC-7, helloPiers wrote:
>
> It's not clear what the type of "out" is, other than it has Stat() and
> Read([]byte) methods, but, assuming it's an io.Reader at least, if you
> examine the return values from Read, like:
> n, err := out.Read(buffer)
> you may get a clue to what's going wrong, for example n might not be the
> full size of the file, there might be an error, etc. Likewise it's worth
> checking the error returned from Stat.
>
>
> It might be that "out" already is a ReadSeekCloser (if it's an *io.File
> for example) in which case you can set Body in the UploadInput just to
> "out":
>
> ...
> Body: out,
> ...
>
> and dispense with all the stuff related to buffer.
>
>
> On Tuesday, August 14, 2018 at 6:18:43 AM UTC+1, Sachin Makaram wrote:
>>
>> Hi,
>>
>> I am trying to upload a local image file to an AWS S3 bucket and return
>> the public URL in Golang. This is the core Golang code I have written to
>> interact with my S3 bucket:
>>
>> creds :=
>> credentials.NewSharedCredentials("/Users/username/.aws/credentials",
>> "default")
>>
>> config := &aws.Config{
>> Region: aws.String("us-west-2"),
>> Credentials: creds,
>> }
>>
>> sess := session.New(config)
>>
>> uploader := s3manager.NewUploader(sess, func(u *s3manager.Uploader) {
>> u.PartSize = 64 * 1024 * 1024
>> u.LeavePartsOnError = true
>> })
>>
>> fmt.Println(header.Filename)
>>
>> fileInfo, _ := out.Stat()
>> var size int64 = fileInfo.Size()
>> fmt.Println("size", size)
>> buffer := make([]byte, size)
>>
>> out.Read(buffer)
>> fileBytes := bytes.NewReader(buffer)
>>
>> result, err := uploader.Upload(&s3manager.UploadInput{
>> Bucket: aws.String("bucket-name"),
>> Key: aws.String(header.Filename),
>> Body: aws.ReadSeekCloser(fileBytes),
>> ContentType: aws.String("image/jpeg"),
>> ACL: aws.String("public-read"),
>> })
>> if err != nil || result == nil {
>> log.Fatalln("Failed to upload", err)
>> }
>>
>> log.Println("Successfully uploaded to", result.Location)
>>
>> With this code, the file is uploaded successfully to my s3 bucket with
>> the correct size in bytes, but when I click on the URL, a black square is
>> displayed instead of the actual image. If I change the ContentType field to
>> allow file types dynamically, when I click on the URL, it downloads the
>> image, but the image cannot be opened because "it may have been damaged."
>> How can I fix this Golang code to just upload an image to an S3 bucket and
>> get the public URL as a result of that upload?
>>
>> This may be more of a debugging question pertaining to AWS S3 than
>> Golang, but any help would be appreciated. Thank you!
>>
>>
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