Thanks a lot, I went back and gave jsonpb a go and finally got it
unmarshalling as desired.
To do so though I had to unmarshal and marshal the response with the
regular json library first, in order to get around some escaped values in
the response (I was receiving a 'bad value in Struct' error:
resJson, err := ioutil.ReadAll(res.Body)
j := make(map[string]interface{})
jbytes, err := json.Marshal(j)
result := &pb.Response{}
r := strings.NewReader(string(jbytes))
if err := jsonpb.Unmarshal(r, result); err != nil {
panic(err)
}
Is this fine to do, or is it super inefficient and will cause problems?
On Tuesday, 15 May 2018 05:09:04 UTC+10, [email protected] wrote:
>
> You need to use the go protobuf json decoder
> https://github.com/golang/protobuf/tree/master/jsonpb
>
> On Monday, 14 May 2018 11:24:06 UTC+8, Luke IC wrote:
>>
>> Hi all,
>>
>> I'm creating a microservice in Go, using protocol buffers and gRPC. It
>> interacts with a third-party API (Snooth) and I'm trying to unmarshal the
>> JSON response into a protobuf struct I've created, using the proto
>> package.
>>
>> Unmarshalling returns an unexpected EOF error.
>>
>>
>> I've summed up the details in full on this question at Stack Overflow:
>> https://stackoverflow.com/questions/50314476/why-does-unmarshalling-this-api-response-return-an-unexpected-eof
>>
>>
>> In addition to the information posted there, I've also tried using
>> strconv.Unquote before unmarshalling in line with the idea that the escaped
>> characters in the API response are causing a double-encode. But this didn't
>> work either.
>>
>> Any help would be greatly appreciated as I've been stuck on this for a
>> while now and feel there's something simple I'm missing.
>>
>>
>> Thanks.
>>
>
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