> > https://research.swtch.com/godata
>
I did read it, but what I was asking is irrelevent to it.
func showInt(x int) {
res := (*[unsafe.Sizeof(x)]byte)(unsafe.Pointer(&x))
for i := range res {
fmt.Printf("%.2x ", res[i])
}
fmt.Println()
}
// showInt(12345)
// 39 30 00 00 00 00 00 00
An integer in it's binary form is stored like above, little endian.
What I mean is how, strings are represented, while converting a string to
[]byte, gives me utf-8 values,
but directly ascessing the underlying memory of string, without converting
it to []byte shows different things.
> > Because in Go the size of an array must be a constant.
> >
> > Ian
>
An array size must be constant, but my real question is?
How come, a uintptr type value returned by unsafe.Sizeof(x), is considered
as const?
and doesn't accept, if uintptr type value is returned by someother function.
I mean, how was it able to differentiate between someother function and
unsafe.Sizeof(x).
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